On Fri, 14 Mar 2008, Henrique Dallazuanna wrote:
> If I understand:
>
> as.Date("2008-03-14") + 5*365
What about leap years? That is 2013-03-13.
> x <- as.Date("2008-03-14")
> xx <- as.POSIXlt(x)
> xx$year <- xx$year+5
> as.Date(xx)
[1] "2013-03-14"
is I think what is being asked for.
> On 14
If I understand:
as.Date("2008-03-14") + 5*365
On 14/03/2008, Jillywadd <[EMAIL PROTECTED]> wrote:
>
> Hello!
>
> I currently have a table of data with a column of start dates and a column
> with some numbers representing years. I need to add these numbers to the
> dates to get an end date. T
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