On Jan 11, 2013, at 3:26 PM, Bjoern Helm wrote:
> Hi,
> thank you. I just came up with
>
> lapply(c(1:length(lst)), function(x) return(lst[[x]][[2]]))
>
>
> but your solution is much more elegant. Although I don't completely
> understand: if lst is the argument of function x[[2]] this should
Hi,
thank you. I just came up with
lapply(c(1:length(lst)), function(x) return(lst[[x]][[2]]))
but your solution is much more elegant. Although I don't completely understand:
if lst is the argument of function x[[2]] this should be iterpreted as
lst[[2]]. Where am I wrong?
Björn
Am 11.01.20
On 01/12/2013 12:40 AM, Bjoern Helm wrote:
Dear R users,I have a list of equally structured lists, how can I access e.g.
all 2nd compontents in those sub-lists?An example:lst <-
list(rep(list(1:3),3), rep(list(4:6),3))> lst[[1]][[1]][[1]][1] 1 2
3[[1]][[2]][1] 1 2 3[[1]][[3]][1] 1 2 3[[2]][[2]][[
lapply(lst, function(x) return(x[[2]]))
On Fri, Jan 11, 2013 at 6:40 AM, Bjoern Helm wrote:
> Dear R users,I have a list of equally structured lists, how can I access e.g.
> all 2nd compontents in those sub-lists?An example:lst <-
> list(rep(list(1:3),3), rep(list(4:6),3))> lst[[1]][[1]][[1]][1]
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