Thanks guys. The first solution with the gsub / lapply works perfectly. The
solution using substrings would work if the times were in a consistent
format, but without the leading zeros and with some parts of the string
absent completely it would need some extra logic to apply. I need something
to a
Hello gavinr,
> I have a character string that represents a time duration. It has an hours
> minutes seconds structure(ish) but with letters denoting units (H,M or S) no
> leading zeros and no placeholder at all where one or other of the units are
> not required.
>
> It looks like this:
>
> t<-c
Regular expressions are the tool for this problem. This pattern
matches your input data:
t <- c("10H20M33S", "1H1M", "1M", "21M9S", "2H55S")
patt <- "^(([0-9]+)H)?(([0-9]+)M)?(([0-9]+)S)?$"
all(grepl(patt, t)) # TRUE
We can use the pattern to extract hour/minute/second components
hms <- lapply(c
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