This is a nice demonstration of the formula interface to aggregate. A
less elegant alternative is to pass lists as arguments.
with(dd,
aggregate(Correct,
by = list(Subject = Subject,
Group = Group),
FUN = function(x) sum(x == 'C')))
Hi:
If you have R 2.11.x or later, one can use the formula version of aggregate():
aggregate(Correct ~ Subject + Group, data = ALLDATA, FUN = function(x)
sum(x == 'C'))
A variety of contributed packages (plyr, data.table, doBy, sqldf and
remix, among others) have similar capabilities.
If you wa
On 05/01/2011 05:28 AM, Kevin Burnham wrote:
HI All,
I have a long data file generated from a minimal pair test that I gave to
learners of Arabic before and after a phonetic training regime. For each of
thirty some subjects there are 800 rows of data, from each of 400 items at
pre and posttest.
Since you did provide a description of your data (e.g., at least
'str(ALLDATA)') so that we know its structure, I will take a guess:
tapply(ALLDATA$Correct, list(ALLDATA$Subject, ALLDATA$Time),
function(x)sum(x=="C"))
On Sat, Apr 30, 2011 at 3:28 PM, Kevin Burnham wrote:
> HI All,
>
> I have a l
HI All,
I have a long data file generated from a minimal pair test that I gave to
learners of Arabic before and after a phonetic training regime. For each of
thirty some subjects there are 800 rows of data, from each of 400 items at
pre and posttest. For each item the subject got correct, there
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