Or use the labels= argument of factor.
On Sun, Jun 28, 2009 at 8:06 AM, Peter Dalgaard wrote:
> Gabor Grothendieck wrote:
>>
>> If you only want to convert them to unique numbers then
>>
>> as.numeric(factor(x))
>>
>> will do that.
>
> Or, use it directly for indexing, as in c(1000,2500,4173,3700)
Gabor Grothendieck wrote:
If you only want to convert them to unique numbers then
as.numeric(factor(x))
will do that.
Or, use it directly for indexing, as in c(1000,2500,4173,3700)[factor(x)]
DEPENDING on LEVEL ORDER, mind you! So make sure you know what the order
is or set it yourself usin
If you only want to convert them to unique numbers then
as.numeric(factor(x))
will do that.
On Sun, Jun 28, 2009 at 7:00 AM, Gregor Povh wrote:
> Thanks Gabor, but in my case not every value ist actually encoded within
> the character string. Vor example, I have an answer category, which is
> "
Thanks Gabor, but in my case not every value ist actually encoded within
the character string. Vor example, I have an answer category, which is
"more than one Mio. $". (not in the column "income"...).
I have the feeling, that there must be an another, straightforward way
or function for tran
Try this. It matches the first numeric string on
each line applying as.numeric to it and then using
c to simplify the resulting list to a numeric vector.
> x <- c("from 1000$ to 2000$", "from 2000$ to 3000$", "more than 3000$",
+ "from 1000$ to 2000$", "from 1000$ to 2000$")
> library(gsubfn)
>
Dear R users,
apologies for this quite simple question. I've tried serverall
approaches, however, could not generate the desired result.
I have a large data frame, which has several cathegories encoded as
character strings, for example.
Name, income, gender, ...
... "from 1000$ to 2000$
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