HI Jim,
This is great!! It is also tricky!!! The problem lies in the choice of
ylim. And looking at the data and choosing ylim based on the maximum and
minimum values of y is a waste of time. And choosing it by other means was
yet much more difficult.
I had to start plotting part of the data with
Hi Ogbos,
The problem is almost certainly with the data. I get the plot I expect
with the sample data that you first posted, so I know that the code
works. If you try thIs what do you get?
oodf<-read.table(text="S/N AB
1-5 64833
2-4 95864
3-3 82322
4-2 95591
5-
Hi Jim
Thanks again for returning to this.
please not that the line "oomean<-as.vector(by(oodf$B,oodf$A,mean))" was
omitted (not sure whether deliberate) after you introduced the standard
error function.
When I used it, empty plot window with the correct axes were generated but
no data was displa
Hi Ogbos,
If I use the example data that you sent, I get the error after this line:
oose<-as.vector(by(oodf$B,oodf$A,std.error))
Error in FUN(X[[i]], ...) : object 'std.error' not found
The reason is that you have not defined std.error as a function, but
as the result of a calculation. When I rew
Hi Ogbos,
This may help:
# assume your data frame is named "oodf"
oomean<-as.vector(by(oodf$B,oodf$A,mean))
oose<-as.vector(by(oodf$B,oodf$A,std.error))
plot(-5:10,oomean,type="b",ylim=c(5,11),
xlab="days (epoch is the day of Fd)",ylab="strikes/km2/day")
dispersion(-5:10,oomean,oose)
Jim
Dear workers,
I have a data of length 1136. Below is the code I use to get the means B.
It worked fine and I had the mean calculated and plotted.
I wish to plot the error bars as well. I already plotted such means with
error bars before. Please see attached for example.
I tried to redo the same p
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