Re: [R] taking daily means from hourly data

2010-07-14 Thread Meissner, Tony (DFW)
rg Subject: Re: [R] taking daily means from hourly data This is one way: df <- data.frame(Time=as.POSIXct("2009-01-01", format="%Y-%m-%d") + seq(0, 60*60*24*365-1, 60*60), lev.morgan=3+runif(24*365), lev.lock2=3+runif(24*365),

Re: [R] taking daily means from hourly data

2010-07-14 Thread Allan Engelhardt
This is one way: df<- data.frame(Time=as.POSIXct("2009-01-01", format="%Y-%m-%d") + seq(0, 60*60*24*365-1, 60*60), lev.morgan=3+runif(24*365), lev.lock2=3+runif(24*365), flow=1000+rnorm(24*365, 200), direction=runif(24*365, 0

Re: [R] taking daily means from hourly data

2010-07-14 Thread Gabor Grothendieck
On Thu, Jul 15, 2010 at 12:52 AM, Meissner, Tony (DFW) wrote: > I have a data frame (morgan) of hourly river flow, river levels and wind > direction and speed thus: >         Time           hour lev.morgan lev.lock2 lev.lock1 flow   direction   > velocity > 1  2009-07-06 15:00:00   15      3.266

[R] taking daily means from hourly data

2010-07-14 Thread Meissner, Tony (DFW)
I have a data frame (morgan) of hourly river flow, river levels and wind direction and speed thus: Time hour lev.morgan lev.lock2 lev.lock1 flow direction velocity 1 2009-07-06 15:00:00 15 3.266 3.274 3.240 1710.6 180.282 4.352 2 2009-07-06 16:00:00