),lst1)
res1[is.na(res1)]<-"*"
res1
# mean n a b c
#1 11 3 1 * *
#2 12 3 * * 1
#3 14 3 * 1 *
A.K.
- Original Message -
From: Alexander Shenkin
To: r-help@r-project.org
Cc:
Sent: Wednesday, March 20, 2013 3:57 PM
Subject: [R] summarize dataframe based on multiple
ashen...@ufl.edu
>> Sent: Wed, 20 Mar 2013 14:57:36 -0500
>> To: r-help@r-project.org
>> Subject: [R] summarize dataframe based on multiple cols, not their
>> combinations
>>
>> Hi folks,
>>
>> I'm trying to figure out how to get summarized data based on
Nice, thanks Ista!
On 3/20/2013 3:18 PM, Ista Zahn wrote:
> How about
>
> library(reshape2)
> mdf.m <- melt(my_df, measure.vars=c("a", "b", "c"))
> mdf.m <- mdf.m[mdf.m$value > 0, ]
>
> ddply(mdf.m, "variable", function(x) c("mean"=mean(x$dat), "n"=nrow(x)))
>
> ?
>
> Best,
> Ista
>
> On Wed,
Will this do?
library(plyr)
ddply(my_df, .(a), summarize, mm = mean(dat), number = length(dat))
John Kane
Kingston ON Canada
> -Original Message-
> From: ashen...@ufl.edu
> Sent: Wed, 20 Mar 2013 14:57:36 -0500
> To: r-help@r-project.org
> Subject: [R] summarize dat
How about
library(reshape2)
mdf.m <- melt(my_df, measure.vars=c("a", "b", "c"))
mdf.m <- mdf.m[mdf.m$value > 0, ]
ddply(mdf.m, "variable", function(x) c("mean"=mean(x$dat), "n"=nrow(x)))
?
Best,
Ista
On Wed, Mar 20, 2013 at 3:57 PM, Alexander Shenkin wrote:
> Hi folks,
>
> I'm trying to figur
Hi folks,
I'm trying to figure out how to get summarized data based on multiple
columns. However, instead of giving summaries for every combination of
categorical columns, I want it for each value of each categorical column
regardless of the other columns. I could do this with three different
co
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