Hi,
Try:
x[x$Species%in%names(sp)[1:2],]
A.K.
On Saturday, February 8, 2014 10:21 PM, Yuanzhi Li
wrote:
Hi, everyone
I met a small problem when I want take a subset from a data frame. The
data frame(x) looks like the followings(10 species with 3 measured
traits):
Species trait1 tra
Hello,
First of all use ?dput to post a data example.
dput(head(x, 20)) # paste the output of this in a post
Now, without a reproducible example it's difficult to say but maybe ?%in%
x[x$Species %in% names(sp)[1:2],]
Hope this helps,
Rui Barradas
Em 09-02-2014 00:03, Yuanzhi Li escreveu:
Hi, everyone
I met a small problem when I want take a subset from a data frame. The
data frame(x) looks like the followings(10 species with 3 measured
traits):
Species trait1trait2 trait3
sp1
sp1
...
sp2
sp2
...
sp10
sp10
...
It would be easy if we want trait values for most abu
Hi, everyone
I met a small problem when I want take a subset from a data frame. The
data frame(x) looks like the followings(10 species with 3 measured
traits):
Species trait1trait2 trait3
sp1
sp1
...
sp2
sp2
...
sp10
sp10
...
It would be easy if we want trait values for most abu
Try this:
DF <- data.frame( "Date" =
c("2009-09-01","2009-09-02","2009-09-03","2009-09-04",
"2009-09-05"), "Data" = c( 10:14 ) )
subset(DF, as.Date(Date) >= '2009-09-02' & as.Date(Date) <= '2009-09-04')
On Tue, Feb 1, 2011 at 11:09 AM, Usuario R wrote:
> Hello,
>
> I have a data frame with one
Hello,
I have a data frame with one column set as the date with function as.Date.
In example:
data.frame( "Date" = c("2009-09-01","2009-09-02","2009-09-03","2009-09-04",
"2009-09-05"), "Data" = c( 10:14 ) )
Date Data
2009-09-01 10
2009-09-02 11
2009-09-03 12
2009-09-04 13
Is there
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