Re: [R] subset columns from list with variable substitution

Thanks Don Please forgive my poor mail-liost etiquette. I had a couple of errors: 1) the counter logic in the loop was "i in name list", my typo in the post. 2) There were typos in the variable list that caused the loop to crash when they were encountered. Thanks for your help, really apprecia

Re: [R] subset columns from list with variable substitution

The select argument to subset() is supposed to name the columns you want to keep. So is the syntax I gave, table[,list1], and it is the correct way when list1 is a character vector (which it is). Your error message says that at least one of the values in list1 is not the name of a column in your d

Re: [R] subset columns from list with variable substitution

Thanks Don but table[,list1] did not work either: Error in `[.data.frame`(table, , list1) : undefined columns selected. I'm guessing my list (list1) is not structured right? Displaying it has no commas, so the whole list may be taken as a single variable rather than a sequence of variables? I

Re: [R] subset columns from list with variable substitution

Instead of subset(table, select=list1) try table[, list1] However, I suspect you have other problems. Particularly, i is not defined when you use i %in% namelist. You may have wanted i in namelist -Don -- Don MacQueen Lawrence Livermore National Laboratory 7000 East Ave., L-627 Livermo

[R] subset columns from list with variable substitution

Hi there, I would like to use a list variable to select columns in a subset from a parent table: I have a data frame "table" with column headers a,b,c,d,e,x,y,z and list variables list1=c("a","b","c","d") list2=c("a","b","x",y","z") namelist=c("peter","paul","mary","jane") group1=c("peter","paul