See suggestion inserted below.
It assumes and requires that every input IP address has the required four
elements.
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 1/8/12 5:11 AM, "Enrico Schumann" wrote:
>
>Hi Andrew,
Hi Andrew,
I am aware, that this is an R-mailing list, but for such tasks (I deal a
lot with huge genomic datasets) I tend to use awk and sed for
preprocessing of data, in case I run into performance problems.
Otherwise for handling of strings in R I recommend stringr library, but
I don't know abo
On 01/08/2012 11:37 AM, jim holtman wrote:
Just a quick followup to the previous post using 4M entries: (20
seconds would seem like a reasonable time for the operation)
ip<- "123.456.789.321" ## example data
df<- data.frame(ip = rep(ip, 4e6), stringsAsFactors=FALSE)
system.time(x<- strs
Just a quick followup to the previous post using 4M entries: (20
seconds would seem like a reasonable time for the operation)
> ip <- "123.456.789.321" ## example data
> df <- data.frame(ip = rep(ip, 4e6), stringsAsFactors=FALSE)
> system.time(x <- strsplit(df$ip, '\\.'))
user system elap
Hi Andrew,
you can use strsplit for a character vector; you do not have to call it
for every element data$ComputerName[i].
If I understand correctly, maybe something like this helps
> ip <- "123.456.789.321" ## example data
> df <- data.frame(ip = rep(ip, 9), stringsAsFactors=FALSE)
> df
Folks,
I have a data frame with 4861469 rows that contains an ip address
xxx.xxx.xxx.xxx as one of the columns. I want to assign a site to each
row based on IP ranges. To do this I have a function to split the ip
address as character into class A,B,C and D components. It works but is
horribly
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