#4 NaN 0.000
#5 NaN 0.000
Hope it helps.
A.K.
- Original Message -----
From: Ozgul Inceoglu
To: arun
Cc: R help
Sent: Thursday, February 14, 2013 10:22 AM
Subject: re:Re: [R] spearman correlation and p-value as a matrix
you are right! I was so happy to find out the p-va
317
> # Otu00209 Otu00218
>#1 NaN -0.12705141
>#2 NaN -0.61522514
>#3 NaN -0.89010286
>#4 NaN 0.03036290
>#5 NaN 0.08266317
>
>A.K.
>
>
>
>- Original Message -
>From: Ozgul Inceoglu
>To: R help
>Cc:
>Sent:
- Original Message -
From: Ozgul Inceoglu
To: R help
Cc:
Sent: Thursday, February 14, 2013 1:10 AM
Subject: Re: [R] spearman correlation and p-value as a matrix
Thank you all for the answers. I really need to learn a lot.
Bu I also discover cor2m(x, y, trim = TRUE, alpha = 0.05)
in ecod
- colnames(res2)
identical(res1,res2)
#[1] TRUE
A.K.
- Original Message -
From: Ozgul Inceoglu
To: arun
Cc:
Sent: Thursday, February 14, 2013 6:17 AM
Subject: re:Re: [R] spearman correlation and p-value as a matrix
Dear Arun,
I bothered you this week alot, but it seems like that y
N
>
>head(resrnew)
># [,1]
>#Otu00022_ag1 0.1309307
>#Otu00029_ag1 NaN
>#Otu00039_ag1 0.1309307
>#Otu00042_ag1 NaN
>#Otu00101_ag1 -0.6546537
>#Otu00105_ag1 NaN
>
>A.K.
>
>
>
>
>- Original Message -
&g
A.K.
----- Original Message -----
From: Ozgul Inceoglu
To: r-help@r-project.org
Cc:
Sent: Wednesday, February 13, 2013 4:48 AM
Subject: [R] spearman correlation and p-value as a matrix
I have two data matrices that I want to make the correlation between each
column from data1 and each column fro
On 02/13/2013 08:48 PM, Ozgul Inceoglu wrote:
I have two data matrices that I want to make the correlation between each
column from data1 and each column from data 2 and also calculate the p-value
Matrices dont have the same size and I tried such a script.
bg<- read.table (file.choose(), heade
I have two data matrices that I want to make the correlation between each
column from data1 and each column from data 2 and also calculate the p-value
Matrices dont have the same size and I tried such a script.
> bg <- read.table (file.choose(), header=T, row.names)
> bg
> Otu00022 Otu00029 Otu
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