O yea sure. So for example:
grid <- read.table("table")
( i havent printed the output, as the table is 20,000 rows X 60 columns)
point_of_interest <- c("row1", "row2")
therefore all the other points in
plot(table)
are labelled green, but these two are labelled red.
But at the minute, becaus
Errr...I'm still not sure how plot(table) gives you read and green
points, but it sounds like the easiest thing to do would be to use the
points() function to come back in and put new green points over the
red ones. E.g.
plot(runif(5000), runif(5000))
points(c(0.5, 0.25), c(0.5, 0.75), col = 2, pc
What sort of plot are you using? I'm not really clear on what your
data as a whole look like: if you use dput() you can create a
representation and we can work from there.
In addition to the resources Josh recommended, the following sites can
direct you to all sorts of graphical goodies, all of wh
I appreciate the reading Thank you. May i ask one final question. If i have:
matrix:
> var1var2 var3
> cell1x x x
> cell2x x x
> cell3x x x
>
> cell4
>
> .
> .
> .
> .
> cell100
and:
vector1 <- c("cell1, "cell5",cell19", "cell
Thanks Josh. I'm quite new, just wondering re:factor levels?
In this example (shamelessly stolen from the internet):
*schtyp*
[1] 0 0 1 0 0 0 1 0 1 0 1 1 1 1 0 0 1 1 1 0
*schtyp.f <- factor(schtyp, labels = c("private", "public"))
schtyp.f*
[1] private private public private private private p
On Tue, Mar 13, 2012 at 5:15 AM, sybil kennelly wrote:
> Thanks Josh. I'm quite new, just wondering re:factor levels?
>
> In this example (shamelessly stolen from the internet):
>
> schtyp
>
> [1] 0 0 1 0 0 0 1 0 1 0 1 1 1 1 0 0 1 1 1 0
>
> schtyp.f <- factor(schtyp, labels = c("private", "public"
Hi Sybil,
You cannot turn a list into a factor. You could do:
cell_data <-c('cell1','cell2')
factor_list <- factor(cell_data)
or if you already have a list, unlist() or as.vector() may convert it
into a vector that you can then convert to a factor.
Cheers,
Josh
On Tue, Mar 13, 2012 at 4:29 A
Hello can anyone help please?
i read two words "cell1", "cell2" into a list. I want to turn this list
into a factor.
> cell_data <-list(c('cell1','cell2'))
> cell_data
[[1]]
[1] "cell1" "cell2"
> factor_list <- factor(cell_data)
Error in sort.list(y) : 'x' must be atomic for 'sort.list'
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