Duncan Murdoch recently (24 July 2008) posted code providing a much more
elegant and efficient approach. (Subject line: truncated normal). Also
there is apparently a function in the msm package which will do this
for you.
cheers,
Rolf Turner
On 25/07/2008, at 2:43
Since the standard normal distribution goes to infinity in both
directions, you can't have random normal constrained to +-1.5.
You can have _truncated_ standard normal, though, if that's really what
you want.
+-1.5 is/are the normal quantiles at pnorm(c(-1.5,1.5)). So if we
generate 500 uniform
Or, as suggested by Duncan Murdoch,
qnorm(runif(500,pnorm(-1.5),pnorm(1.5)))
--- On Fri, 25/7/08, jim holtman <[EMAIL PROTECTED]> wrote:
> From: jim holtman <[EMAIL PROTECTED]>
> Subject: Re: [R] simple random number generation
> To: "dxc13" <[EMAIL PROT
Generate more than you need and then just keep 500 of them:
> x <- rnorm(3000) # make sure we have enough
> y <- x[(x > -1.5) & (x < 1.5)][1:500] # keep 500 0f them
> hist(y)
>
On Thu, Jul 24, 2008 at 7:35 PM, dxc13 <[EMAIL PROTECTED]> wrote:
>
> useR's,
>
> I want to randomly generate 500 numb
useR's,
I want to randomly generate 500 numbers from the standard normal
distribution, i.e. N(0,1), but I only want them to be generated in the range
-1.5 to 1.5. Does anyone have a simple way to do this?
Thanks,
dxc13
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