On Wed, Oct 9, 2013 at 11:49 AM, Berend Hasselman wrote:
>
> On 09-10-2013, at 13:50, Ronald Peterson wrote:
>
>> Hi,
>>
>> New to R here. Lots of fun. Still rather green though.
>>
>> I'd like to select unique items from a list that looks like this (for
>> example):
>>
>>> xyz
>> $x
>> [1] 8 6
Very cool! Thanks Berend and arun.
R.
On Wed, Oct 9, 2013 at 2:49 PM, Berend Hasselman wrote:
>
> On 09-10-2013, at 13:50, Ronald Peterson wrote:
>
> > Hi,
> >
> > New to R here. Lots of fun. Still rather green though.
> >
> > I'd like to select unique items from a list that looks like thi
Thanks. That's not quite what I'm looking for, but it's good see different
ways to slice and dice data.
In my example, the one duplicated x,y pair would 9,9, so I would want to
reduce the original list to
> xyz
$x
[1] 8 6 9 0 0 3 9 7 1
$y
[1] 1 2 9 5 1 2 0 9 2
$z
[1] 5 6 9 0 5 1 1 7 3
and if
On 09-10-2013, at 13:50, Ronald Peterson wrote:
> Hi,
>
> New to R here. Lots of fun. Still rather green though.
>
> I'd like to select unique items from a list that looks like this (for
> example):
>
>> xyz
> $x
> [1] 8 6 9 0 0 3 9 7 1 9
> $y
> [1] 1 2 9 5 1 2 0 9 2 9
> $z
> [1] 5 6 9 0 5
[1] 4
A.K.
From: Ronald Peterson
To: arun
Cc: R help
Sent: Wednesday, October 9, 2013 1:52 PM
Subject: Re: [R] select unique by multiple values
Thanks. That's not quite what I'm looking for, but it's good see different
ways to slice and dice
Hi,
Not sure about your expected output.
xyz<-
list(x=c(8,6,9,0,0,3,9,7,1,9),y=c(1,2,9,5,1,2,0,9,2,9),z=c(5,6,9,0,5,1,1,7,3,4))
indx<-sort(unique(unlist(lapply(xyz[1:2],function(u)
which(!duplicated(u))),use.names=FALSE)))
xyz[1:2]<-lapply(xyz[1:2],function(u) u[!duplicated(u)])
xyz[3]$z<-
Hi,
New to R here. Lots of fun. Still rather green though.
I'd like to select unique items from a list that looks like this (for
example):
> xyz
$x
[1] 8 6 9 0 0 3 9 7 1 9
$y
[1] 1 2 9 5 1 2 0 9 2 9
$z
[1] 5 6 9 0 5 1 1 7 3 4
I'd like to select unique (x,y), while preserving association wi
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