On Jan 20, 2013, at 9:27 AM, David Winsemius wrote:
On Jan 20, 2013, at 8:26 AM, Sam Steingold wrote:
* Bert Gunter [2013-01-19 22:26:46 -0800]:
But David W. and Bill Dunlap gave you solutions that also work and
are
much faster, no?!
Yes, indeed, and I am now using David's solution as
On Jan 20, 2013, at 8:26 AM, Sam Steingold wrote:
* Bert Gunter [2013-01-19 22:26:46 -0800]:
But David W. and Bill Dunlap gave you solutions that also work and
are
much faster, no?!
Yes, indeed, and I am now using David's solution as it is fast
(enough), simple and concise.
I am a bit
> * Bert Gunter [2013-01-19 22:26:46 -0800]:
>
> But David W. and Bill Dunlap gave you solutions that also work and are
> much faster, no?!
Yes, indeed, and I am now using David's solution as it is fast
(enough), simple and concise.
Thanks a lot to David, Bill, Rui, and arun for their answers (t
But David W. and Bill Dunlap gave you solutions that also work and are
much faster, no?!
-- Bert
On Sat, Jan 19, 2013 at 9:41 PM, Sam Steingold wrote:
>> * Rui Barradas [2013-01-18 21:02:20 +]:
>>
>> Try the following.
>>
>> complete.cases(f) & apply(f, 1, function(x) all(x == x[1]))
>
> th
> * Rui Barradas [2013-01-18 21:02:20 +]:
>
> Try the following.
>
> complete.cases(f) & apply(f, 1, function(x) all(x == x[1]))
thanks, this works, but is horribly slow (dim(f) is 766,950x2)
--
Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000
http://www.chil
apply(f,1,function(x) all(duplicated(x)|duplicated(x,fromLast=TRUE)&!is.na(x)))
#[1] TRUE FALSE FALSE FALSE
A.K.
- Original Message -
From: Sam Steingold
To: r-help@r-project.org
Cc:
Sent: Friday, January 18, 2013 3:53 PM
Subject: [R] select rows with identical columns fr
1 1 1
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf
> Of Sam Steingold
> Sent: Friday, January 18, 2013 12:53 PM
> To: r-help@r-project.org
> Subjec
On Jan 18, 2013, at 1:02 PM, Rui Barradas wrote:
> Hello,
>
> Try the following.
>
> complete.cases(f) & apply(f, 1, function(x) all(x == x[1]))
>
>
> Hope this helps,
>
> Rui Barradas
>
> Em 18-01-2013 20:53, Sam Steingold escreveu:
>> I have a data frame with several columns.
>> I want to
Hello,
Try the following.
complete.cases(f) & apply(f, 1, function(x) all(x == x[1]))
Hope this helps,
Rui Barradas
Em 18-01-2013 20:53, Sam Steingold escreveu:
I have a data frame with several columns.
I want to select the rows with no NAs (as with complete.cases)
and all columns identical
I can do
Reduce("==",f[complete.cases(f),])
but that creates an intermediate data frame which I would love to avoid
(to save memory).
> * Sam Steingold [2013-01-18 15:53:21 -0500]:
>
> I have a data frame with several columns.
> I want to select the rows with no NAs (as with complete.cases)
> a
I have a data frame with several columns.
I want to select the rows with no NAs (as with complete.cases)
and all columns identical.
E.g., for
--8<---cut here---start->8---
> f <- data.frame(a=c(1,NA,NA,4),b=c(1,NA,3,40),c=c(1,NA,5,40))
> f
a b c
1 1 1 1
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