Re: [R] select elements and transpose

2009-12-30 Thread Dennis Murphy
Hi: An alternative is the following: # This regenerates your dataset: xx <- list(matrix(1:9, nrow = 3, byrow = TRUE), matrix(10:18, nrow = 3, byrow = TRUE), matrix(19:27, nrow = 3, byrow = TRUE)) # Flatten matrix elements of each component into vectors: xxf <- lapply(xx,

Re: [R] select elements and transpose

2009-12-30 Thread Henrique Dallazuanna
If I understand, you can try this: array(do.call(rbind, xx), c(3, 3, 3)) On Wed, Dec 30, 2009 at 11:45 AM, Muhammad Rahiz wrote: > Hi all, > > Given the following, > >> xx > [[1]] >    V1 V2 V3 > [1,]  1  2  3 > [2,]  4  5  6 > [3,]  7  8  9 > [[2]] >    V1 V2 V3 > [1,]10 11  12 > [2,]13 14  15

[R] select elements and transpose

2009-12-30 Thread Muhammad Rahiz
Hi all, Given the following, > xx [[1]] V1 V2 V3 [1,] 1 2 3 [2,] 4 5 6 [3,] 7 8 9 [[2]] V1 V2 V3 [1,]10 11 12 [2,]13 14 15 [3,]16 17 18 [[3]] V1 V2 V3 [1,]19 20 21 [2,]22 23 24 [3,]25 26 27 how do i extract elements in each file so that after transpose, it looks