Try this also:
t(sapply(my.list, '[', seq(max(sapply(my.list, length)
On Sat, Nov 20, 2010 at 9:06 AM, Robert Ruser wrote:
> Hello,
> Let's assume that one has a list:
> my.list <- list(a=c(1,2,3,4),b=4,c=c(1:7))
>
> I want to save my.list as a matrix in .txt file. Because of different
> le
Hi Mohamed,
It works. Thank you very much.
Best,
Robert
2010/11/20 :
> Hi Robert,
>
> Try to do this
>
> Len <- max(sapply(my.list, length))
>
> fun1 <- lapply(my.list, function(x){
> c(x, rep(0, Len))[1:Len]
> })
> do.call(rbind, fun1)
>
> M
> Regards
Hello,
Let's assume that one has a list:
my.list <- list(a=c(1,2,3,4),b=4,c=c(1:7))
I want to save my.list as a matrix in .txt file. Because of different
length we can put NA or 0.
Effect (row.names a, b and c are not necessary)
a 1 2 3 4 0 0 0
b 4 0 0 0 0 0 0
c 1 2 3 4 5 6 7
How to do it?
Than
3 matches
Mail list logo
