Hi all,
Thanks for the suggestions.
What I ended up using was
x=aggregate(dat,by=list(dat$DOY,dat$Hour),mean)
where is my matrix and DOY is day of year. This gives me hourly means for
each day (apologies for not being more specific with my question). This
works for now but I'll probably want to
On Jul 11, 2011, at 9:23 AM, Joshua Wiley wrote:
Hi,
Take a look at package "zoo", perhaps something like:
require(zoo)
x <- rnorm(1) # hypothetical data
m <- rollapply(zoo(x), width = 100, FUN = mean, by = 100)
Definitely a better answer, but if all your rolling averages were of
the f
On Jul 11, 2011, at 11:23 , M. B wrote:
> Hello,
> I am running R on Linux and have a column of data 1 points long. I would
> like to take a moving average of say 100 points at a time, so I end up with
> one column of 100 points. What is the simplest way of doing this? I would
> like to be a
Hi,
Take a look at package "zoo", perhaps something like:
require(zoo)
x <- rnorm(1) # hypothetical data
m <- rollapply(zoo(x), width = 100, FUN = mean, by = 100)
Another (bit more of a hack) option would be:
## convert vector to matrix byrows with 100 columns per row
## (where 100 is the n
Hello,
I am running R on Linux and have a column of data 1 points long. I would
like to take a moving average of say 100 points at a time, so I end up with
one column of 100 points. What is the simplest way of doing this? I would
like to be able to adjust the width of the averaging blocks.
Th
5 matches
Mail list logo
