Re: [R] reshape data frame when one column has unequal number of entries

2015-04-23 Thread Dimitri Liakhovitski
mitri > Liakhovitski > Sent: Thursday, 23 April 2015 23:15 > To: r-help > Subject: [R] reshape data frame when one column has unequal number of > entries > > Hello! > > I have my data frame x with 2 character columns: > > x <- data.frame(a = numeric(), b =

Re: [R] reshape data frame when one column has unequal number of entries

2015-04-23 Thread PIKAL Petr
f Maybe you want to remove extra white space form your values. It is mentioned somewhere in help pages to regular expressions Cheers Petr > -Original Message- > From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Dimitri > Liakhovitski > Sent: Thursday, April 23,

Re: [R] reshape data frame when one column has unequal number of entries

2015-04-23 Thread Duncan Mackay
351 Email: home: mac...@northnet.com.au -Original Message- From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Dimitri Liakhovitski Sent: Thursday, 23 April 2015 23:15 To: r-help Subject: [R] reshape data frame when one column has unequal number of entries Hello! I have my

[R] reshape data frame when one column has unequal number of entries

2015-04-23 Thread Dimitri Liakhovitski
Hello! I have my data frame x with 2 character columns: x <- data.frame(a = numeric(), b = I(list())) x[1:3,"a"] = 1:3 x[[1, "b"]] <- "a, b, c" x[[2, "b"]] <- "d, e" x[[3, "b"]] <- "f" x$a = as.character(x$a) x$b = as.character(x$b) x str(x) I need to produce this data frame: 1 a 1 b 1 c 2