Re: [R] Replace a for loop with a function

Eekhout, I. wrote on 09/19/2011 10:16:17 AM: > > Hi all, > > I would like to replace the for loop in the code below with a function > to improve the speed and to make the script more efficient. > The loop creates a vector of integers (x) with the probability of f for > each integer. > The lengt

Re: [R] Replace a for loop with a function

sorry, there is a superfluous bracket at the end of the line, it should be read as sample(1:3,50,prob=c(0.5,0.15,0.35),replace=T) Am 19.09.2011 19:08, schrieb Eik Vettorazzi: > Hi Iris, > maybe I misinterpret this, but I think in the end it all comes down to > sample(1:3,50,prob=c(0.5,0.15,0.35),r

Re: [R] Replace a for loop with a function

Hi Iris, maybe I misinterpret this, but I think in the end it all comes down to sample(1:3,50,prob=c(0.5,0.15,0.35),replace=T)) cheers Am 19.09.2011 17:16, schrieb Eekhout, I.: > Hi all, > > I would like to replace the for loop in the code below with a function > to improve the speed and to mak

[R] Replace a for loop with a function

Hi all, I would like to replace the for loop in the code below with a function to improve the speed and to make the script more efficient. The loop creates a vector of integers (x) with the probability of f for each integer. The length of f is variable, but sums to 1. I tried to use a function

Re: [R] replace a for loop

Well actually, in that case, I don't think it is really necessary to replace the loop because it is quite fast with the small size I have. But I thought it would help me to understand how would vectorization work and how to use the *apply functions. Thanks anyway for your piece of advice! Ivan

Re: [R] replace a for loop

Hi how many objects do you have in a list? Loop is ineffective if you use several nested loops and/or there is some unnecessary mimic of simple function. e.g. you can use this set.seed(666) x <- runif(10) vysled <- 0 for(i in 1:length(x)) { if(vysled > x[i]) vysled <- vysled else vysled <- x[i

Re: [R] replace a for loop

After reading the R news, I've tried this code and it works: > rapply(list(names(test),test), write.csv, file="filename.csv", append=T, row.names=F) However, the output is structured like this: names(test)[[1]] names(test)[[2]] etc... test[[1]] test[[2]] etc... I would like to alternate names(

Re: [R] replace a for loop

On Wed, Feb 10, 2010 at 9:50 AM, Ivan Calandra wrote: > I'm still quite new in R and I don't really understand this whole > "vectorization" thing. > See [1] for an article on vectorisation and loops in R. Liviu [1] http://www.r-project.org/doc/Rnews/Rnews_2008-1.pdf _

[R] replace a for loop

Hi everybody! I'm still quite new in R and I don't really understand this whole "vectorization" thing. For now, I use a for loop (and it works fine), but I think it would be useful to replace it. I want to export the result of a test statistic, which is stored as a list, into a csv file. I t

Re: [R] replace a for loop with lapply or relative

Have you considered using a different data structure: > # change the data structure > x <- data.frame( + type=rep(c('x1', 'x2', 'x3'), each=100), + high=c(d[,4], d[,5], d[,6]), + value=c(d[,1], d[,2], d[,3])) > head(x) type high value 1 x10 0.8936737 2 x10 -1.047298

[R] replace a for loop with lapply or relative

Dear helpers. I often need to make dichotomous variables out of continuous ones (yes, I realize the problems with throwing away much of the information), but I then like to check the min and max of each category. I have the following simple code to do this that cuts each variable (x1,x2,x3) at th