Try this also:
ls[colSums(sapply(ls, '[[', 'Acc')) > 0]
On Sun, Nov 7, 2010 at 9:07 AM, Matthew Finkbeiner <
matthew.finkbei...@mq.edu.au> wrote:
> I have a list of data frames like this:
>
> a<- data.frame(x=runif(10), y = runif(10), Acc = 1)
> b<- data.frame(x=runif(10), y = runif(10), Acc =
Thank you Jim (and others who responded off list). This does the
trick for me perfectly:
ls[sapply(ls, function(x) all(x$Acc == 1))]
Thanks again!
Matthew
On Sun, Nov 7, 2010 at 11:34 PM, jim holtman wrote:
> Is this what you are asking; this accepts any dataframe that has at
> least one Ac
Is this what you are asking; this accepts any dataframe that has at
least one Acc = 1; changing 'any' to 'all' means all Acc==1. Play
around and get what you need:
> ls<- list(a,b)
> ls
[[1]]
x y Acc
1 0.26550866 0.2059746 1
2 0.37212390 0.1765568 1
3 0.57285336 0.68702
I have a list of data frames like this:
a<- data.frame(x=runif(10), y = runif(10), Acc = 1)
b<- data.frame(x=runif(10), y = runif(10), Acc = 0)
ls<- list(a,b)
and I want to remove the data frames from ls that have Acc values other than 1.
How do I do that?
Thanks for any help!
Matthew
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