Re: [R] recursive List extraction question

2008-12-12 Thread Henrique Dallazuanna
Try this: rapply(L, c)[grep("\\.val$", names(rapply(L, c)))] On Fri, Dec 12, 2008 at 7:55 AM, wrote: > Dear all, > I've got a list > L <- list(L1 = list > (foo = "bar" > , SL = NULL > ) > , L2 = list > ( > foo = "bar" > , SL = l

[R] recursive List extraction question

2008-12-12 Thread Dominik.Cullmann
Dear all, I've got a list L <- list(L1 = list (foo = "bar" , SL = NULL ) , L2 = list ( foo = "bar" , SL = list (SSL1 = list (DF = data.frame(val = 21, foo = "bar") , DFOO = list(foo = "foo