Hello,
Inline.
Em 10-06-2015 13:03, khatri escreveu:
Hey sorry for my typing.
I have actually used the same format with % that is
No you have not, like others allready have told you.
You need %H:%M:%S not H:M:S.
strptime(dd,"%d/%m %H:%M:%S")
[1] "2015-01-21 11:11:11 GMT"
Hope this helps,
Your example is not the same as the answers you have received. Look again.
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No really, what Jim said: you need the % for H:M:S as well.
> dd<-c("21/01 11:11:11")
> strptime(dd,"%d/%m %H:%M:%S")
[1] "2015-01-21 11:11:11 EST"
On Wed, Jun 10, 2015 at 8:03 AM, khatri wrote:
> Hey sorry for my typing.
> I have actually used the same format with % that is
>
>
>> dd<-c("21/01
Hey sorry for my typing.
I have actually used the same format with % that is
> dd<-c("21/01 11:11:11")
> strptime(dd,"%d/%m H:M:S")
[1] NA
it is giving NA.
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Hi khatri,
strptime("6/20 21:56:32","%m/%d %H:%M:%S")
[1] "2015-06-20 21:56:32 AEST"
You forgot the % signs in the format for H:M:S
Jim
On Wed, Jun 10, 2015 at 8:20 PM, khatri wrote:
> My date column is in following format : "%m/%d H:M:S"
> There is not mention of year in the data.So how can I
Hi!
10.06.2015, 13:20, khatri wrote:
My date column is in following format : "%m/%d H:M:S"
There is not mention of year in the data.So how can I read this using
strptime function.
I have tried strptime(dates,"%m/%d H:M:S") but this is returning NA.
Thanks
How about:
strptime(dates,"%m/%d %H:%
My date column is in following format : "%m/%d H:M:S"
There is not mention of year in the data.So how can I read this using
strptime function.
I have tried strptime(dates,"%m/%d H:M:S") but this is returning NA.
Thanks
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