Derek,
the 0*m part zeros out everything in the matrix, expect for the NA's,
0*NA=NA by definition. If we add this to the y[ col(m) ] matrix, then
NA+anything=NA, but 0+anything=anything.
G.
ps. please answer to the list (as well)
On Fri, Feb 01, 2008 at 08:52:50AM -0500, Derek Cyr wrote:
>
Actually, you don't need apply. If there are no NA's then it is
very easy:
m[] <- y[ col(m) ]
If you want to keep the NA's then it is a bit more tricky:
m[] <- 0*m + y[ col(m) ]
G.
On Thu, Jan 31, 2008 at 07:03:51PM -0800, dxc13 wrote:
>
> useR's,
>
> Consider:
> y <- c(20, 25, 30)
> > m <
useR's,
Consider:
y <- c(20, 25, 30)
> m <- matrix(c(0.0,1,NA,0.5,1.25,0.75, 0.5, NA,
> NA),byrow=TRUE,nrow=3,ncol=3)
> m
[,1] [,2] [,3]
[1,] 0.0 1.00 NA
[2,] 0.5 1.25 0.75
[3,] 0.5 NA NA
For each numeric value, I want to replace them with their corresponding
y-value. The result s
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