Hello,
Em 12-10-2014 18:26, David Winsemius escreveu:
On Oct 12, 2014, at 8:45 AM, Rui Barradas wrote:
Hello,
Try the following.
do.call(rbind, lapply(a, '[[', "var1"))
do.call(rbind, lapply(a, '[[', "var2"))
Could perhaps (untested) make it more general with:
do.call(rbind, lapply(a, '[
On Oct 12, 2014, at 8:45 AM, Rui Barradas wrote:
> Hello,
>
> Try the following.
>
> do.call(rbind, lapply(a, '[[', "var1"))
> do.call(rbind, lapply(a, '[[', "var2"))
Could perhaps (untested) make it more general with:
do.call(rbind, lapply(a, '[[', names(a[[1]])[1]))
do.call(rbind, lapply(a,
Hello,
Try the following.
do.call(rbind, lapply(a, '[[', "var1"))
do.call(rbind, lapply(a, '[[', "var2"))
Hope this helps,
Rui Barradas
Em 12-10-2014 07:14, Cesar Caballero escreveu:
Hi all,
I have an array of lists. All lists have the same names and the vectors inside
each name have the
Hi all,
I have an array of lists. All lists have the same names and the vectors inside
each name have the same dimension.
For instance,
a[1:4]
[[1]]
[[1]]$var1
[1] 1 2 3 4 5
[[1]]$var2
[1] 6 7
[[2]]
[[2]]$var1
[1] 2 4 6 8 10
[[2]]$var2
[1] 12 14
[[3]]
[[3]]$var1
[1] 3 6 9 12 15
[[3
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