Thank you very much, do.call is, of course, much more elegant!
Dimitri
On Wed, Apr 22, 2009 at 9:58 PM, jim holtman wrote:
> 'do.call' is your friend::
>
>> a<-data.frame(a=1,b=2,c=3)
>> b<-data.frame(a=c(4,7),b=c(5,8),c=c(6,9))
>> c<-data.frame(a=c(10,13,16),b=c(11,14,17),c=c(12,15,18))
>> X<-li
Replying to my own post. I found the following solution:
full.frame<-as.data.frame(matrix(nrow=0,ncol=3))
names(full.frame)<-c("a","b","c")
for(j in 1:length(X)) {full.frame<-rbind(full.frame,X[[j]])}
(full.frame)
Is there a more elegant solution?
Thank you!
Dimitri
On Wed, Apr 22, 2009 at 9:36
'do.call' is your friend::
> a<-data.frame(a=1,b=2,c=3)
> b<-data.frame(a=c(4,7),b=c(5,8),c=c(6,9))
> c<-data.frame(a=c(10,13,16),b=c(11,14,17),c=c(12,15,18))
> X<-list()
> X[[1]]<-a
> X[[2]]<-b
> X[[3]]<-c
> do.call(rbind, X)
a b c
1 1 2 3
2 4 5 6
3 7 8 9
4 10 11 12
5 13 14 15
6 16
oject.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Dimitri Liakhovitski
Sent: Wednesday, April 22, 2009 6:36 PM
To: R-Help List
Subject: [R] rbind data frames stored in a list
Hello everyone!
I have a list X with 3 elements, each of which is a data frame, for example:
a<-dat
On Apr 22, 2009, at 8:36 PM, Dimitri Liakhovitski wrote:
Hello everyone!
I have a list X with 3 elements, each of which is a data frame, for
example:
a<-data.frame(a=1,b=2,c=3)
b<-data.frame(a=c(4,7),b=c(5,8),c=c(6,9))
c<-data.frame(a=c(10,13,16),b=c(11,14,17),c=c(12,15,18))
X<-list()
X[[1
Hello everyone!
I have a list X with 3 elements, each of which is a data frame, for example:
a<-data.frame(a=1,b=2,c=3)
b<-data.frame(a=c(4,7),b=c(5,8),c=c(6,9))
c<-data.frame(a=c(10,13,16),b=c(11,14,17),c=c(12,15,18))
X<-list()
X[[1]]<-a
X[[2]]<-b
X[[3]]<-c
(X)
How can I most effectively transf
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