On 2012-07-22 13:09, Henrik Singmann wrote:
Hi Mary,
I think the good old t-test is what you want:
Maybe, but calculating p-values with absolutely no consideration
of assumptions is pure folly. It may well be that Mary has some
assumptions in mind, but the way the question was posed does not
i
On 12-07-22 3:37 PM, Mary Kindall wrote:
I have a value
a=300
observation (x) = sample(1:50)
How to find a p-value from this. I need to show that "a" is different fom
mean(x).
Thanks
This question doesn't really make sense. sample(1:50) gives you the
same sample as 1:50 does, just in a dif
HI,
Probably ?pnorm
x1<-mean(x)
x1
[1] 25.5
> pnorm(25.5,mean=300)
[1] 0
A.K.
- Original Message -
From: Mary Kindall
To: r-help@r-project.org
Cc:
Sent: Sunday, July 22, 2012 3:37 PM
Subject: [R] pvalue calculate
I have a value
a=300
observation (x) = sample(1:50)
How t
Hi Mary,
I think the good old t-test is what you want:
x <- sample(1:50)
t.test(x, mu = 300)
gives:
One Sample t-test
data: x
t = -133.2, df = 49, p-value < 0.00022
alternative hypothesis: true mean is not equal to 300
95 percent confidence interval:
21.36 29.64
sample
I have a value
a=300
observation (x) = sample(1:50)
How to find a p-value from this. I need to show that "a" is different fom
mean(x).
Thanks
--
-
Mary Kindall
Yorktown Heights, NY
USA
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