The fact that it works when you pass your i values "by hand" should alert you
that perhaps your loop control does not do what you think it does.
Consider:
Your version:
for(i in 1:6 - 1)
What you probably meant:
for(i in 1:(6 - 1)) print(i)
The error is created on the first iteration of your l
for (i in 1:(ncol(MD_dist) - 1)){
...
}
Even better, replace
1:(n-1)
with
seq_len(n-1)
The latter does what you want (and empty integer vector) when n is 1;
the former would give c(1,0).
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Tue, Jul 7, 2015 at 2:11 PM, David Barron wr
You need to put the expression on the right of the colon in your for
statement in parenthesis:
for (i in 1:(ncol(MD_dist) - 1)){
...
}
On 7 July 2015 at 19:00, Karl Schilling wrote:
> Dear All:
>
> I want to use seq() inside a for-loop and use the looping counter i as the
> "by" argument in seq(
Dear All:
I want to use seq() inside a for-loop and use the looping counter i as
the "by" argument in seq(). Here is some exemplary data and code:
# set up some data
distances <- c(0, NA, NA, NA, NA, NA,
5, 0, NA, NA, NA, NA,
5, 2, 0, NA, NA, NA,
18
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