Matthias Kohl wrote:
> one addition ...
>
>> Hello Ricardo,
>>
>> another solution could be using package distr:
>>
>> library(distr)
>> A <- c(18,18,18,19,20,21,22,23,24,25,26,27,28)
>> DA <- DiscreteDistribution(A)
>> # maybe
>> # support(DA)
>> # plot (DA)
>>
>> B <- c(82,83,84,85,85,86,87,88
one addition ...
> Hello Ricardo,
>
> another solution could be using package distr:
>
> library(distr)
> A <- c(18,18,18,19,20,21,22,23,24,25,26,27,28)
> DA <- DiscreteDistribution(A)
> # maybe
> # support(DA)
> # plot (DA)
>
> B <- c(82,83,84,85,85,86,87,88,89,90,91,91,92)
> DB <- DiscreteDistrib
Hello Ricardo,
another solution could be using package distr:
library(distr)
A <- c(18,18,18,19,20,21,22,23,24,25,26,27,28)
DA <- DiscreteDistribution(A)
# maybe
# support(DA)
# plot (DA)
B <- c(82,83,84,85,85,86,87,88,89,90,91,91,92)
DB <- DiscreteDistribution(B)
# support(DB)
# plot(DB)
DC <-
> i have two vectors (A and B) and i need create another vector (C)
> from the subtraction of A's values with the B's values. How can i
> estimate the probability of C's values if i have differents values
> combinations of A and B that can result in the same value? like 90
> -20 = 70 and 91 - 2
Hi all,
i'm new R user and i need some help:
i have two vectors (A and B) and i need create another vector (C) from the
subtraction of A's values with the B's values. How can i estimate the
probability of C's values if i have differents values combinations of A and B
that can result in the sam
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