-project.org] On
Behalf Of Patrick Burns
Sent: Friday, November 25, 2011 1:41 PM
To: r-help@r-project.org; i...@hotmail.com
Subject: Re: [R] perfectionism
Did you try:
z[f]
On 25/11/2011 19:23, Jack Tanner wrote:
> I have a named vector:
>
>> z<- c(1, 2, 3, 2)
>> names(
jim holtman gmail.com> writes:
> > match(f, names(z))
> [1] 2 3
Jim, thanks so much, that's right on.
Patrick, thanks to you too, but yours is not the same as what I asked:
> z <- c(3,4,5,4)
> names(z)<- c("a","b","c","b")
> z[f]
b c
4 5
Yours returns the actual values in z, not the indexes
Did you try:
z[f]
On 25/11/2011 19:23, Jack Tanner wrote:
I have a named vector:
z<- c(1, 2, 3, 2)
names(z)<- c("a","b","c","b")
f<- c("b","c")
I want to know the index in z of the first occurrence of each of the values in
f.
One implementation is
sapply(f, function(x) which(names(z)==x
Try this:
> z <- c(1, 2, 3, 2)
> names(z) <- c("a","b","c","b")
> f <- c("b","c")
> match(f, names(z))
[1] 2 3
> # if you want the names
> x <- match(f, names(z))
> names(x) <- f
> x
b c
2 3
On Fri, Nov 25, 2011 at 2:23 PM, Jack Tanner wrote:
> I have a named vector:
>
>> z <- c(1, 2, 3, 2)
>>
I have a named vector:
> z <- c(1, 2, 3, 2)
> names(z) <- c("a","b","c","b")
> f <- c("b","c")
I want to know the index in z of the first occurrence of each of the values in
f.
One implementation is
> sapply(f, function(x) which(names(z)==x)[1])
b c
2 3
Is which() smart enough to stop when i
5 matches
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