On Wed, 17 Dec 2008 20:07:08 +0100, GOUACHE David
wrote:
argument which I will pass on to subset() somewhere inside my function.
I would use the example of .() function from plyr package in this case:
.<-function (...){
structure(as.list(match.call()[-1]), class = "quoted")
}
myfuncti
This thread may help?
https://stat.ethz.ch/pipermail/r-help/2007-November/145345.html
On Wed, 17 Dec 2008 20:07:08 +0100, "GOUACHE David"
wrote:
> Hello R-helpers,
>
> I'm writing a long function in which I manipulate a certain number of
> datasets. I want the arguments of said function to allo
I wrote a dirty hack last time I faced this problem, I'll be curious
to see what is the proper way of dealing with the scoping and
evaluation rules.
library(datasets)
myfunction<-function(table, extraction) {
table2<-subset(table,extraction)
return(table2)
}
condition1 <- quote(iris$S
Available free for the typing are the functions for the default and
the dataframe methods of subset:
> subset.default
function (x, subset, ...)
{
if (!is.logical(subset))
stop("'subset' must be logical")
x[subset & !is.na(subset)]
}
> subset.data.frame
function (x, subset, se
Hello R-helpers,
I'm writing a long function in which I manipulate a certain number of datasets.
I want the arguments of said function to allow me to adapt the way I do this.
Among other things, I want my function to have an argument which I will pass on
to subset() somewhere inside my functio
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