Very sorry that I ignore the question type.Yest,it's not an R question.
Many thanks for your answer.
--
QQ: 1733768559
At 2015-02-05 18:26:01,"peter dalgaard" wrote:
>
>On 05 Feb 2015, at 09:20 , meng wrote:
>
>> Hi all:
>> If I want to test whether the mean of a set of normal distrib
On 05 Feb 2015, at 09:20 , meng wrote:
> Hi all:
> If I want to test whether the mean of a set of normal distributed data is
> different from a value(e.g. 0), I can use one sample t test . But if the data
> is not normal distributed,what kind of method should be used?
>
Not really an R quest
Hi all:
If I want to test whether the mean of a set of normal distributed data is
different from a value(e.g. 0), I can use one sample t test . But if the data
is not normal distributed,what kind of method should be used?
Many thanks!
My best.
[[alternative HTML version delete
---
> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
> project.org] On Behalf Of rr400
> Sent: Thursday, October 16, 2008 6:38 AM
> To: r-help@r-project.org
> Subject: Re: [R] One-sample test for p
>
>
> Thanks for your responses. I know it is bad form asking about these
> thi
Thanks for your responses. I know it is bad form asking about these things
but i was really having trouble getting my head around it, and i wanted to
make sure that the cause wasn't due to the commands i was entering into R.
At least now i know it's a conceptual error i am making rather than a
tec
Duncan Murdoch wrote:
This isn't really about R, and maybe it is homework, but now that we
got you in the appropriate frame of mind:
(a) p values should look at "this or more unfavourable" events. You
have arranged things so that that translates to -6.13 or _lower_. I.e.
you're looking a
On 10/16/2008 7:35 AM, Peter Dalgaard wrote:
rr400 wrote:
Hi, i am doing a statistics course and am having trouble with an exercise
where i need to determine whether my success rate at something is higher
than 80%.
I was successful in 29 out of 60 trials, so these were the commands i
entered i
rr400 wrote:
Hi, i am doing a statistics course and am having trouble with an exercise
where i need to determine whether my success rate at something is higher
than 80%.
I was successful in 29 out of 60 trials, so these were the commands i
entered into R:
n=60
p.hat=29/n
p.0=0.8
se.0=sqrt(p.0*
Hi, i am doing a statistics course and am having trouble with an exercise
where i need to determine whether my success rate at something is higher
than 80%.
I was successful in 29 out of 60 trials, so these were the commands i
entered into R:
>n=60
>p.hat=29/n
>p.0=0.8
>se.0=sqrt(p.0*(1-p.0)/n)
>
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