[R] na.pass option in ccf function

2012-06-06 Thread Dario Mavec
Hi everyone, I have been working with the ccf function recently, and in particular to do my calculations I have been using "na.action = na.pass". I noticed that the help documentation mentions that with this option the computed estimate may not be a valid autocorrelation sequence and was wond

Re: [R] na.pass

2008-10-13 Thread jim holtman
If you want to remove the "N", then you can work with the indices: > x [1] NA "B" NA "B" "B" NA "N" "A" "B" "B" "A" NA "A" "N" "N" "N" "A" "B" "B" "A" > # if you want the indices of the non-"N", then > (indx <- which(is.na(x) | x != "N")) [1] 1 2 3 4 5 6 8 9 10 11 12 13 17 18 19 20 >

Re: [R] na.pass

2008-10-13 Thread Laura Bonnett
I have a data frame. It has lots of patient information, their age, their gender, etc etc. I need to keep all this information whilst selecting relevant rows. So, in the example of code I provided I want to remove all those patients who have entry N in the column with.Wcode. The dimension of th

Re: [R] na.pass

2008-10-13 Thread jim holtman
Not sure exactly what you are trying to do since you did not provide commented, minimal, self-contained, reproducible code. Let me take a guess in that you also have to test for NAs: > x <- sample(c("N", "A", "B", NA), 20, TRUE) > x [1] "A" "A" "B" NA "N" NA NA "B" "B" "N" "N" "N" "B" "A" NA

[R] na.pass

2008-10-13 Thread Laura Bonnett
Hi All, I have a data frame which has columns comprised mainly of "NA"s. I know there are functions na.pass and na.omit etc which can be used in these situations however I can't them to work in this case. I have a function which returns the data according to some rule i.e. removal of N in this c