On Tue, Aug 16, 2011 at 6:40 PM, Sam Steingold wrote:
>> * Ista Zahn [2011-08-16 18:31:00 -0400]:
>> On Tue, Aug 16, 2011 at 6:29 PM, Ista Zahn wrote:
>>> Hi Tia,
>
> "tia" == "thanks in advance" :-)
*facepalm* Thanks Sam, one day I'll learn internet acronyms...
>
>> AB3 <- AB2[order(AB$Time,
> * Ista Zahn [2011-08-16 18:31:00 -0400]:
> On Tue, Aug 16, 2011 at 6:29 PM, Ista Zahn wrote:
>> Hi Tia,
"tia" == "thanks in advance" :-)
> AB3 <- AB2[order(AB$Time, decreasing=TRUE), ]
> AB4 <- AB3[!duplicated(AB3[c("Name", "Open")]), ]
thanks!
--
Sam Steingold (http://sds.podval.org/) on
On Tue, Aug 16, 2011 at 6:29 PM, Ista Zahn wrote:
> Hi Tia,
>
> On Tue, Aug 16, 2011 at 6:00 PM, Sam Steingold wrote:
>> I have two datasets:
>> A with columns Open and Name (and many others, irrelevant to the merge)
>> B with columns Time and Name (and many others, irrelevant to the merge)
>>
>>
Hi Tia,
On Tue, Aug 16, 2011 at 6:00 PM, Sam Steingold wrote:
> I have two datasets:
> A with columns Open and Name (and many others, irrelevant to the merge)
> B with columns Time and Name (and many others, irrelevant to the merge)
>
> I want the dataset AB with all these columns
> Open from A -
I have two datasets:
A with columns Open and Name (and many others, irrelevant to the merge)
B with columns Time and Name (and many others, irrelevant to the merge)
I want the dataset AB with all these columns
Open from A - a difftime (time of day)
Time from B - a difftime (time of day)
Name (same
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