Thanks everyone! I finally got some code to work (thanks to William Dunlap).
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wdunlap tibco.com
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf Of Ellen S.
> Sent: Friday, July 22, 2011 10:02 AM
> To: r-help@r-project.org
> Subject: [R] matched pairs
>
> Hi all,
>
> I am hopin
Hi all,
I am hoping to keep certain rows of my data set. These are rows whose value
in column X is equal to the value in column X for another row. For example:
1 1
2 1
3 2
4 3
5 4
6 4
>From this I would want the following:
1 1
2 1
5 4
6 4
I am struggling with the for loop. Here is wh
David,
tkanks für your comment, the code and the link.
You are right: "arbitrary" is a better word than "exact" pair matching.
I took the term "one-to-one exact matching" from the paper "MatchIt:
Nonparametric Preprocessing for Parametric Causal Inference" (p. 6):
http://gking.harvard.edu/matchit
Thank´s a lot, Patrick!
That´s what I was looking for...
Zitat von Patrick Connolly <[EMAIL PROTECTED]>:
> On Wed, 16-Apr-2008 at 11:58AM +0200, Udo wrote:
>
>
> |> I only "need" line 1, 6 and 9. To show this,
> |> I added "needed" by hand.
> |>
> |>age school out1 out2 needed
> |> 1
Udo <[EMAIL PROTECTED]> wrote in
news:[EMAIL PROTECTED]:
> Daniel,
> thank you!
>
> I want to perfrom the simplest way of matching:
> a one-to-one exact match (by age and school):
> for every case in "treat" find ONE case (if there is one) in
> "control" . The cases in "control" that could be ma
On Wed, 16-Apr-2008 at 11:58AM +0200, Udo wrote:
|> I only "need" line 1, 6 and 9. To show this,
|> I added "needed" by hand.
|>
|>age school out1 out2 needed
|> 11 10 9.5 1.1 yes
|> 21 10 9.5 2.0 no
|> 31 10 9.5 3.5 no
|> 4
ioned
> question is yes, there is a reason, then we would need to know the criteria
> on which to base the coding for this variable. What makes a yes a yes and a
> no a no?
>
> Cheers,
> Daniel
>
>
>
>
> -
> cuncta stricte discussurus
> ---
Gesendet: Wednesday, April 16, 2008 5:59 AM
An: r-help@r-project.org
Betreff: Re: [R] Matched pairs with two data frames
Patrick,
my intention was, to perform a one-to-one exact match, which pairs each
treated unit with ONE control unit (without replacement), using my two
confounders (age, school
Patrick,
my intention was, to perform a one-to-one exact match, which pairs each treated
unit with ONE control unit (without replacement), using my two confounders
(age, school) for matching.
Patrick Connolly schrieb:
On Mon, 14-Apr-2008 at 08:37AM +0200, Udo wrote:
|> Zitat von Peter Alspach <[
On Mon, 14-Apr-2008 at 08:37AM +0200, Udo wrote:
|> Zitat von Peter Alspach <[EMAIL PROTECTED]>:
|>
|> > Udo
|> >
|> > Seems you might want merge()
|> >
|> > HTH ...
|> >
|> > Peter Alspach
|>
|> Thank you Peter and Jorge,
|>
|> but as I had written in my last sentence,
|> "Merge doesn´t do
;, but maybe there is a sophisticated
solution with "merge", I could not bring light to.
Udo
>
> > -Original Message-
> > From: [EMAIL PROTECTED]
> > [mailto:[EMAIL PROTECTED] On Behalf Of Udo
> > Sent: Monday, 14 April 2008 6:41 a.m.
> > To: r-h
Hi Udo,
Perhaps
> merge(treat,control)
does what you need.
I hope this helps,
Jorge
On Sun, Apr 13, 2008 at 2:41 PM, Udo <[EMAIL PROTECTED]> wrote:
> Hi,
> I have a frame "treat" and want to find matched pairs in the data frame
> "control". In the matched (combined) data frame there should
Udo
Seems you might want merge()
HTH ...
Peter Alspach
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of Udo
> Sent: Monday, 14 April 2008 6:41 a.m.
> To: r-help@r-project.org
> Subject: [R] Matched pairs with two data f
Hi,
I have a frame "treat" and want to find matched pairs in the data frame
"control". In the matched (combined) data frame there should be two
variables (0/1),indicating the "source" of the data (treat or control),
so that it is possibe to set a "filter" (extraxt/select data).
#Here are the dataf
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