Re: [R] list of list

You can let lapply() do the preallocation and the looping for you with ASL <- lapply(1:5, function(j) lapply(1:5, function(i) i^j)) Bill Dunlap TIBCO Software wdunlap tibco.com On Mon, Feb 16, 2015 at 9:46 AM, Jeff Newmiller wrote: > You have two named objects when your goal is to have one

Re: [R] list of list

Thanks to Jim, Peter and Jeff who all saw the solution! Best wishes Troels Den 16-02-2015 kl. 18:46 skrev Jeff Newmiller: You have two named objects when your goal is to have one that contains five others. ASL <- vector( "list", 5 ) for (j in 1:5){ ASL[[j]] <- vector( "list", 5 ) for (i

Re: [R] list of list

You have two named objects when your goal is to have one that contains five others. ASL <- vector( "list", 5 ) for (j in 1:5){ ASL[[j]] <- vector( "list", 5 ) for (i in 1:5) { ASL[[j]][[i]] <- i^j } } --- Jeff New

Re: [R] list of list

On 16 Feb 2015, at 17:43 , Troels Ring wrote: > Dear friends - this is simple I know but I can figure it out without your > help. > I have for each of 2195 instances 10 variables measured at specific times > from 6 to several hundred, so if I just take one of the instances, I can make > a lis

Re: [R] list of list

Is this what you mean: ASL <- list() for (j in 1:5){ RES <- list() for (i in 1:5) RES[[i]] <- i ^ j # create list ASL[[j]] <- RES # store 'list of list' } Jim Holtman Data Munger Guru What is the problem that you are trying to solve? Tell me what you want to do, not how you want t

[R] list of list

Dear friends - this is simple I know but I can figure it out without your help. I have for each of 2195 instances 10 variables measured at specific times from 6 to several hundred, so if I just take one of the instances, I can make a list of the 10 variables together with their variable times.

Re: [R] List of List in Data Frame

On Jan 31, 2011, at 8:45 PM, Gundala Viswanath wrote: Dear sirs, I have a data that is generated like this: dat1 <- data.frame(V1 = rep(1, 5), V2 = sample(c(40:45), 5)) dat2 <- data.frame(V1 = sample(c(0,1), 5, replace = TRUE), V2 = sample(c(40:45), 5, replace = TRUE)) What I want to do

[R] List of List in Data Frame

Dear sirs, I have a data that is generated like this: > dat1 <- data.frame(V1 = rep(1, 5), V2 = sample(c(40:45), 5)) > dat2 <- data.frame(V1 = sample(c(0,1), 5, replace = TRUE), V2 = > sample(c(40:45), 5, replace = TRUE)) What I want to do is to obtain a data frame that contain list of list. >

Re: [R] list of list objects

?unlist -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Rajasekaramya Sent: Friday, November 21, 2008 2:14 PM To: r-help@r-project.org Subject: [R] list of list objects hi there, I have a list of list objects i need to remove the top layer [[1]] [1

Re: [R] list of list objects

?unlist -Original Message- From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Rajasekaramya Sent: Friday, November 21, 2008 2:14 PM To: r-help@r-project.org Subject: [R] list of list objects hi there, I have a list of list objects i need to remove the top layer [[1]] [1

Re: [R] list of list objects

Will one of these two solutions work for you: > x <- list(list(1,2), list(3,4), list(5,6)) > x [[1]] [[1]][[1]] [1] 1 [[1]][[2]] [1] 2 [[2]] [[2]][[1]] [1] 3 [[2]][[2]] [1] 4 [[3]] [[3]][[1]] [1] 5 [[3]][[2]] [1] 6 > > lapply(x, "[[", 1) [[1]] [1] 1 [[2]] [1] 3 [[3]] [1] 5 > lapply(x,

[R] list of list objects

hi there, I have a list of list objects i need to remove the top layer [[1]] [1].0 "ABC" "DEF""LMN" [1].1 "WER" "ERT" "TRY" [[2]] [2].0 "ASD","wer""qwe" [2].1 "wdv""ghj""ggj" I wanna avoid the top layer...that is [[1]] [[2]] shouldnt be there just a simple list is wat i need. [1].0 "ABC" "DEF"