; 1/4 on [0,2] .
>
> -- Bert
>
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf Of Carrie Li
> Sent: Saturday, 26 June 2010 1:28 PM
> To: r-help
> Subject: [R] integration of two normal density
>
>
: Re: [R] integration of two normal density
Your intuition is wrong and R is right.
Why should the product of two probability density functions be a normalized
pdf also?
-- as is trivially seen with two uniforms on [0,2], with pdf= 1/2, product =
1/4 on [0,2] .
-- Bert
-Original Message
On Fri, 2010-06-25 at 23:28 -0400, Carrie Li wrote:
> Hello everyone,
>
> I have a question about integration of two density function
> Intuitively, I think the value after integration should be 1, but they are
> not. Am I missing something here ?
>
> > t=function(y){dnorm(y, mean=3)*dnorm(y/2, m
hool of Medicine
Johns Hopkins University
Ph. (410) 502-2619
email: rvarad...@jhmi.edu
- Original Message -
From: Carrie Li
Date: Friday, June 25, 2010 11:29 pm
Subject: [R] integration of two normal density
To: r-help
> Hello everyone,
>
> I have a question about integration
-help
Subject: [R] integration of two normal density
Hello everyone,
I have a question about integration of two density function
Intuitively, I think the value after integration should be 1, but they are
not. Am I missing something here ?
> t <- function(y){dnorm(y, mean=3)*dnorm(y/2, me
Hello everyone,
I have a question about integration of two density function
Intuitively, I think the value after integration should be 1, but they are
not. Am I missing something here ?
> t=function(y){dnorm(y, mean=3)*dnorm(y/2, mean=1.5)}
> integrate(t, -Inf, Inf)
0.3568248 with absolute error
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