This one seems to have slipped through the cracks, but I'll take a stab at
it:
I don't think there's an (easy) general solution but there are two direct
ways to get at the idea.
If you are generally only seeking to do things like: x[order(x)] would
sort(x) work for you?
More generally, this can
If I create an aggregation like this:
aggregate(lastYear[,8:10],list(Stadium=lastYear$STAD),mean)
I'll get a new data frame, which I can order if I assign it like this:
newFrame <- aggregate(lastYear[,8:10],list(Stadium=lastYear$STAD),mean)
newFrame[order(newFrame$TEMP),]
But.. if I just want t
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