Re: [R] if else statement in loop

e(1:3, .Label = c("samas4", "samas5", "samas6" ), class = "factor")), .Names = c("FID", "IID"), class = "data.frame", row.names = c(NA, -3L)) > -Original Message- > From: Kate Ignatius [mailto:kate.ignat...@g

Re: [R] if else statement in loop

is column X$IID1new != '' does not exist in X > > Here you clearly ask for nonexistent column, and why the heck you want to > select column by number of rows? > >> as.character(as.matrix(X[,(2*nrow(X)+1)])) > Error in `[.data.frame`(X, , (2 * nrow(X) + 1)) : >

Re: [R] if else statement in loop

2 * nrow(X) + 1)) : undefined columns selected So based on your toy data frames, what shall be the result after your computation. Regards Petr > -Original Message----- > From: r-help-boun...@r-project.org [mailto:r-help-bounces@r- > project.org] On Behalf Of Kate Ignatius > Se

[R] if else statement in loop

I have two data frames For simplicity: X= V1 V2 V3 V4 V5 V6 samas4 samas5 samas6 samas4_father samas5_mother samas6_sibling samas4 samas5 samas6 samas4_father samas5_mother samas6_sibling samas4 samas5 samas6 samas4_father samas5_mother samas6_sibling Y= FID IID FAM01 samas4 FAM01 samas5 FAM0