Carlos Nasher via R-help r-project.org> writes:
>
[snip]
> I need to evaluate the Hypergeometric Function of the 2nd kind (Tricomi
> confluent hypergeometric function). Therefore I'm using the kummerU
> function from the fAsianOptions package. It seems to me that kummerU is
> giving wrong resul
Hello R helpers,
I need to evaluate the Hypergeometric Function of the 2nd kind (Tricomi
confluent hypergeometric function). Therefore I'm using the kummerU
function from the fAsianOptions package. It seems to me that kummerU is
giving wrong results. Here's an example:
library("fAsianOptions")
ku
On 19-03-2012, at 16:54, statfan wrote:
> Thanks for your advice. I actually meant to ask about the "pmvt" for the
> distribution function. Viewing the source code "pmvt" uses the function
> "mvt" which uses the function "probval" which sources the fortran code:
>
No it doesn't "source". It
Thanks for your advice. I actually meant to ask about the "pmvt" for the
distribution function. Viewing the source code "pmvt" uses the function
"mvt" which uses the function "probval" which sources the fortran code:
Fortran("mvtdst", N = as.integer(n), NU = as.integer(df),
LOWER = as.d
To view the source of (most) functions, simply type funcname without
parentheses: here, you get
> dmvt
function (x, delta, sigma, df = 1, log = TRUE, type = "shifted")
{
if (df == 0)
return(dmvnorm(x, mean = delta, sigma = sigma, log = log))
if (is.vector(x)) {
x <- matrix
Is there any way to know how the "dmvt" function computes the hypergeometric
function needed in the calculation for the density of multivariate t
distribution?
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Sent from the
Hi,
I hope somebody can help me on how to use the hypergeometric function. I did
read through the R documentation on hypergeometric but not really sure what it
means.
I would like to evaluate the hypergeometric function as follows:
F((2*alpha+1)/2, (2*alpha+2)/2 , alpha+1/2, betasq/etasq).
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