Thanks, Don!
Appreciated your detailed explanation.
On Thu, Sep 1, 2011 at 11:28 AM, MacQueen, Don wrote:
> Even though it's not needed, here's a small followup.
>
> I usually use this
> split(x, paste(x$let,x$g))
>
> But since
>split(x, list(x$let,x$g))
> works, so does
> split(x, x
Even though it's not needed, here's a small followup.
I usually use this
split(x, paste(x$let,x$g))
But since
split(x, list(x$let,x$g))
works, so does
split(x, x[,c('let','g')])
> all.equal( split(x, x[,c('let','g')]) , split(x,list(x$let,x$g)))
[1] TRUE
As to which is the best, hard t
Thanks for the great helps from David, Jim and Liviu. It solved my problem.
Appreciated!
On Thu, Sep 1, 2011 at 11:01 AM, David Winsemius wrote:
>
> On Sep 1, 2011, at 1:53 PM, Changbin Du wrote:
>
> HI, Dear R community,
>>
>> I want to split a data frame by using two variables: let and g
>>
>
On Sep 1, 2011, at 1:53 PM, Changbin Du wrote:
HI, Dear R community,
I want to split a data frame by using two variables: let and g
x = data.frame(num =
c(10,11,12,43,23,14,52,52,12,23,21,23,32,31,24,45,56,56,76,45), let =
letters[1:5], g = 1:2)
x
num let g
1 10 a 1
2 11 b 2
3
On Thu, Sep 1, 2011 at 7:53 PM, Changbin Du wrote:
> HI, Dear R community,
>
> I want to split a data frame by using two variables: let and g
>
It's not clear what you want to do, but investigate the following:
> require(plyr)
Loading required package: plyr
> ddply(x, .(let, g), function(y) mean(
try this:
> split(x, list(x$let, x$g))
$a.1
num let g
1 10 a 1
11 21 a 1
$b.1
num let g
7 52 b 1
17 56 b 1
$c.1
num let g
3 12 c 1
13 32 c 1
$d.1
num let g
9 12 d 1
19 76 d 1
$e.1
num let g
5 23 e 1
15 24 e 1
On Thu, Sep 1, 2011 at 1:53 PM,
HI, Dear R community,
I want to split a data frame by using two variables: let and g
> x = data.frame(num =
c(10,11,12,43,23,14,52,52,12,23,21,23,32,31,24,45,56,56,76,45), let =
letters[1:5], g = 1:2)
> x
num let g
1 10 a 1
2 11 b 2
3 12 c 1
4 43 d 2
5 23 e 1
6 14 a 2
7
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