Hi Sasa,
Those latitude look equidistant with a separation of 0.05.
I guess you want to calculate the zonal mean along the latitude, right?
#estimate the lower and upper latitude for the cut
lat.dist=0.05 #equidistant spacing along latitude
lat.min=min(df$LAT,na.rm=T)-lat.dist/2
lat.max=max(df$LA
On further thought -- and subject to my prior interpretation -- I
think a foolproof way of truncating to 4 decimal digits is to treat
them as character strings rather than numerics and use regex
operations:
> with(df,tapply(TK.QUADRANT,
> sub("(\\.[[:digit:]]{4}).*","\\1",as.character(LAT)),mean)
On Thu, Nov 15, 2018 at 10:40 AM Boris Steipe wrote:
>
> Use round() with the appropriate "digits" argument. Then use unique() to
> define your groups.
No.
> round(c(.124,.126),2)
[1] 0.12 0.13
As I understand it, the OP said he wanted the last decimal to be ignored.
The OP also did not speci
Use round() with the appropriate "digits" argument. Then use unique() to
define your groups.
HTH,
B.
> On 2018-11-15, at 11:48, sasa kosanic wrote:
>
> Dear All,
>
> I would very much appreciate the help with following:
> I need to calculate the mean of different lat/long points that shoul
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