Thank you very much. This definitely helps me out.
Math
Jeff Newmiller wrote
>
> There are many resources for learning regular expressions (e.g.
> http://gnosis.cx/publish/programming/regular_expressions.html). Once you
> understand the basics you will probably be able to refer to the ?regex
>
0 and 1 means zero or 1 match.
Want to remove the word "Energy"?
gsub("( Energy){0,1},{0,1} Inc[.]{0,1}", "", DF)
On Thu, May 31, 2012 at 11:45 AM, mdvaan wrote:
> Thanks! That works like a charm, but I am not sure if I fully understand the
> syntax. I looked at the gsub page but still couldn't
There are many resources for learning regular expressions (e.g.
http://gnosis.cx/publish/programming/regular_expressions.html). Once you
understand the basics you will probably be able to refer to the ?regex help
page for specific tools. After you have waded through a tutorial, the following
ex
Thanks! That works like a charm, but I am not sure if I fully understand the
syntax. I looked at the gsub page but still couldn't figure it out. What
does the pattern part (",{0,1} Inc[.]{0,1}") do? What do the 0 and 1 within
the curly brackets refer to? Also, what if, for example, I would want to
Try this where you qualify how many characters you might match:
> gsub(",{0,1} Inc[.]{0,1}", "", DF)
[1] "Aetna""Alexander's" "Allegheny Energy"
On Wed, May 30, 2012 at 6:05 PM, mdvaan wrote:
> Hi,
>
> I have a vector like this:
>
> DF <- c("Aetna, Inc.", "Alexander's Inc.", "A
Hi,
I have a vector like this:
DF <- c("Aetna, Inc.", "Alexander's Inc.", "Allegheny Energy, Inc")
For each element in the vector I would like to remove the "incorporated"
info, so that my vector looks like this:
DF <- c("Aetna", "Alexander's", "Allegheny Energy")
That means that I have to str
6 matches
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