Re: [R] growing dataframes with rbind

2009-02-24 Thread Jorge Ivan Velez
Dear all, Here is one more way to go though using rep() and then matrix(): > rows <- 1:3 > matrix(rep(rows,5),ncol=5) [,1] [,2] [,3] [,4] [,5] [1,]11111 [2,]22222 [3,]33333 HTH, Jorge On Tue, Feb 24, 2009 at 1:43 PM, Gabor Grothe

Re: [R] growing dataframes with rbind

2009-02-24 Thread Gabor Grothendieck
Suppose we want 3 rows and the ith row should have 5 columns of i. Create a list whose ith component is the ith row and rbind them: > rows <- 1:3 > do.call(rbind, lapply(rows, rep, 5)) [,1] [,2] [,3] [,4] [,5] [1,]11111 [2,]22222 [3,]333

Re: [R] growing dataframes with rbind

2009-02-24 Thread Greg Snow
ical Data Center Intermountain Healthcare greg.s...@imail.org 801.408.8111 > -Original Message- > From: r-help-boun...@r-project.org [mailto:r-help-boun...@r- > project.org] On Behalf Of Alexy Khrabrov > Sent: Tuesday, February 24, 2009 11:02 AM > To: r-h...@stat.math.ethz.ch > Su

[R] growing dataframes with rbind

2009-02-24 Thread Alexy Khrabrov
I'm growing a large dataframe by composing new rows and then doing row <- compute.new.row.somehow(...) d <- rbind(d,row) Is this a fast/preferred way? Cheers, Alexy __ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEA