tmp.out.sort <- tmp.out[, order(names(tmp.out))]
tmp.out.sort <- tmp.out[, order(names(tmp.out)), drop=FALSE]
>From your description of misbehavior with a single column,
I think the drop=FALSE argument will provide the protection you need.
Then you will not need the if clause.
See
?`[.data.fram
Sedges Vascular
> Subject: Re: [R] function output with for loop and if statement
> From: gavin.simp...@ucl.ac.uk
> To: awell...@hotmail.com
> CC: r-help@r-project.org
> Date: Thu, 23 Apr 2009 09:18:17 +0100
>
> On Wed, 2009-04-22 at 15:51 -0400, aaron wells wrote:
>>
: markle...@verizon.net
> To: awell...@hotmail.com
> Subject: Re: [R] function output with for loop and if statement
>
> Hi Aaron: i just looked quickly because I have to go but try wrapping braces
> around the last if else like
> below and see if that helps. if you have multiple st
On Wed, 2009-04-22 at 15:51 -0400, aaron wells wrote:
> Hello all, turns out i'm having a bad R week. I am at my wits end
> with a function that I am trying to write. When I run the lines of
> code outside of a function, I get the desired output. When I wrap the
> lines of code into a function i
2009 15:24:24 -0500
From: markle...@verizon.net
To: awell...@hotmail.com
Subject: Re: [R] function output with for loop and if statement
Hi Aaron: i just looked quickly because I have to go but try wrapping braces
around the last if else like
below and see if that helps. if you have multiple
Hello all, turns out i'm having a bad R week. I am at my wits end with a
function that I am trying to write. When I run the lines of code outside of a
function, I get the desired output. When I wrap the lines of code into a
function it doesn't work as expected. Not sure what is going on her
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