Well, I believe, given the original statement of the problem, that it
is philosophically wrong to use the gsub approach. What if there are
50 underscores instead of 5, and you want to extract the characters
after the 23rd underscore? By using gsub, you are trying to fight
against the pattern of und
A safer way to make sure you don't match the underscore:
> gsub("[^_]*_[^_]*_([^_]*).*", "\\1", "abcd_efgh_X_12ab3_dfsfd")
[1] "X"
On Thu, Feb 10, 2011 at 2:06 PM, Henrique Dallazuanna wrote:
> So, a way could be:
>
> gsub("(.*)_(.*)_(.*)_.*", "\\3", "abcd_efgh_X_12ab3_dfsfd")
>
>
So, a way could be:
gsub("(.*)_(.*)_(.*)_.*", "\\3", "abcd_efgh_X_12ab3_dfsfd")
On Thu, Feb 10, 2011 at 3:47 PM, Soumendra wrote:
> Hi Henrique,
>
> I believe your solution is wrong as it is fitted to find 12ab3,
> whereas Yan seems to be asking for the characters after the second
> unders
Hi Henrique,
I believe your solution is wrong as it is fitted to find 12ab3,
whereas Yan seems to be asking for the characters after the second
underscore and before the third underscore.
For example, gsub(".*_.*_(.*)_.*", "\\1",
"abcd_efgh_X_12ab3_dfsfd") would still yield 12ab3 even though,
Try this:
gsub(".*_.*_(.*)_.*", "\\1", "abcd_efgh_12ab3_dfsfd")
On Thu, Feb 10, 2011 at 9:42 AM, Yan Jiao wrote:
> Dear R gurus,
>
>
>
> If I got a vector with string characters like "abcd_efgh_12ab3_dfsfd",
> how could I extract "12ab3", which is the characters after second
> underscore and be
Dear R gurus,
If I got a vector with string characters like "abcd_efgh_12ab3_dfsfd",
how could I extract "12ab3", which is the characters after second
underscore and before the third underscore?
Tons of thanks
yan
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