Thanks everyone for different solutions.
Every solution works very well. For my purpose, this function sink does what
I was looking for.
Andrija
On Wed, Mar 16, 2011 at 4:23 PM, Roman Luštrik wrote:
> How about?
>
> sink("andrija.csv")
> l
> sink()
>
> --
> View this message in context:
> http:
The optimal way of doing it depends on how you want to use the result. An
easy way has been recommended - if you have
boo <- list(first=data.frame(a=1:5, b=2:6), second=data.frame(a=6:10,
b=7:11))
.. then
sink("boo.txt")
boo # or: print(boo)
sink()
... will put it all in the same file, the sa
How about?
sink("andrija.csv")
l
sink()
--
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Hi,
You could try this (others surely have better solutions):
out_file <- file("file.csv", open="a") #creates a file in append mode
for (i in seq_along(l)){
write.table(names(l)[i], file=out_file, sep=",", dec=".",
quote=FALSE, col.names=FALSE, row.names=FALSE) #writes the name of the
list
Soryy, I didn't explain well what I want. I would like to have a table in
csv on txt file like this:
$A
q1q2
aa 1 3
bb 2 check
cc check 5
$B
q1 q2
aa check 4
bb 1 5
The same as write.csv of any data frame.
On Wed, Mar 16, 2011 at 4:03 PM, Henrique Dallazua
Use dput:
dput(l, file = "l_str.txt")
Then, to read again:
l <- dget(file = 'l_str.txt')
On Wed, Mar 16, 2011 at 11:55 AM, andrija djurovic wrote:
> Hi everybody.
>
> I have list like this:
>
> l<-list(data.frame(q1=c(1,2,"check"),q2=c(3,"check",5)),
> data.frame(q1=c("check",1),q2=c(4,5)))
>
Hi everybody.
I have list like this:
l<-list(data.frame(q1=c(1,2,"check"),q2=c(3,"check",5)),
data.frame(q1=c("check",1),q2=c(4,5)))
names(l)<-c("A","B")
rownames(l[[1]])<-c("aa","bb","cc")
rownames(l[[2]])<-c("aa","bb")
Every object has the same number of columns but different number of rows.
D
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