> eval(parse(text = "iris[iris$Sepal.Width > 4,]"))
Sepal.Length Sepal.Width Petal.Length Petal.Width Species
16 5.7 4.4 1.5 0.4 setosa
33 5.2 4.1 1.5 0.1 setosa
34 5.5 4.2 1.4 0.2 setosa
>
The code I posted does work if you use it as I explained, not
as you changed it. Executing strings is probably not a very
R-ish thing to do but if that's your aim use eval and parse:
s <- "iris["iris$Sepal.Width > 4,]"
eval(parse(text = s))
On Tue, Aug 12, 2008 at 10:35 AM, Dries Knapen <[EMAIL
Dries Knapen-2 wrote:
>
> Hi,
>
> Thanks for your reply. However, this didn't work exactly as I needed
> it to since the expression is dynamically built as a character vector
>
> i.e. not executed as
> e <- expression(Sepal.Width > 4)
>
> but as
> e <- expression("Sepal.Width > 4")
>
> in
On 12 Aug 2008, at 17:00, Gabor Grothendieck wrote:
Executing strings is probably not a very
R-ish thing to do
I know - but as far as I can see there was no other way around in
this case...
but if that's your aim use eval and parse:
s <- "iris["iris$Sepal.Width > 4,]"
eval(parse(text = s
Hi,
Thanks for your reply. However, this didn't work exactly as I needed
it to since the expression is dynamically built as a character vector
i.e. not executed as
e <- expression(Sepal.Width > 4)
but as
e <- expression("Sepal.Width > 4")
in which case subset() throws an error (must evaluat
Try this:
> e <- expression(Sepal.Width > 4)
> subset(iris, eval(e), select = "Sepal.Length")
Sepal.Length
16 5.7
33 5.2
34 5.5
> subset(iris, eval(e))
Sepal.Length Sepal.Width Petal.Length Petal.Width Species
16 5.7 4.4 1.5 0.4 s
Hi,
Based on user input, I wrote a function that creates a list which
looks like:
> str(list)
List of 4
$ varieties: chr [1:12] "temp.26_time.5dagen_biorep.1" "time.
5dagen_temp.26_biorep.2" "temp.18_time.5dagen_biorep.1" "temp.18_time.
5dagen_biorep.2" ...
$ temp : Factor w/ 2 level
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