Re: [R] dynamically creating functions in r

2011-10-05 Thread Carl Witthoft
Another way to build functions "from scratch" : > func<-'x^2+5' > funcderiv<- D(parse(text=func), 'x') ) > newtparam <- function(zvar) {} > body(newtparam)[2] <- parse(text=paste('newz <- (',func,')/eval(funcderiv)',collapse='')) > body(newtparam)[3] <- parse(text=paste('return(invisible

Re: [R] dynamically creating functions in r

2011-10-05 Thread William Dunlap
1] 2 Bill Dunlap Spotfire, TIBCO Software wdunlap tibco.com > -Original Message- > From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On > Behalf Of honeyoak > Sent: Wednesday, October 05, 2011 7:57 AM > To: r-help@r-project.org > Subject: [R]

Re: [R] dynamically creating functions in r

2011-10-05 Thread Duncan Murdoch
On 05/10/2011 10:57 AM, honeyoak wrote: it is possible to dynamically create functions in R using lists? what I want to do is something like this: a = list() for (i in 1:10) a[[i]] = function(seed = i) runif(seed) so that when I call a[i] I get random draws 1,2,i unfortunately

Re: [R] dynamically creating functions in r

2011-10-05 Thread Sarah Goslee
Hi, On Wed, Oct 5, 2011 at 10:57 AM, honeyoak wrote: > it is possible to dynamically create functions in R using lists? what I want > to do is something like this: > >      a = list() >      for (i in 1:10) a[[i]] = function(seed = i) runif(seed) > > so that when I call a[i] I get random draws 1,

[R] dynamically creating functions in r

2011-10-05 Thread honeyoak
it is possible to dynamically create functions in R using lists? what I want to do is something like this: a = list() for (i in 1:10) a[[i]] = function(seed = i) runif(seed) so that when I call a[i] I get random draws 1,2,i unfortunately R only uses the last i . I would also like